-16x^2+10x+10=5

Solution for -16x^2+10x+10=5 equation:

-16x^2+10x+10=5

We move all terms to the left:

-16x^2+10x+10-(5)=0

We add all the numbers together, and all the variables

-16x^2+10x+5=0

a = -16; b = 10; c = +5;
Δ = b2-4ac
Δ = 102-4·(-16)·5
Δ = 420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{420}=\sqrt{4*105}=\sqrt{4}*\sqrt{105}=2\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{105}}{2*-16}=\frac{-10-2\sqrt{105}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{105}}{2*-16}=\frac{-10+2\sqrt{105}}{-32}
$